RSA加解密原理与数学证明
Modulo:
(a-b)%c = (a%c)-(b%c) ○1
(a+b)%c = (a%c)+(b%c) ○2
Regarding to the RSA Algorithm:
ed ≡ 1 (mod φ(n))
=> ed = rφ(n)+1 ○3
Regarding to t[……]阅读全文
Modulo:
(a-b)%c = (a%c)-(b%c) ○1
(a+b)%c = (a%c)+(b%c) ○2
Regarding to the RSA Algorithm:
ed ≡ 1 (mod φ(n))
=> ed = rφ(n)+1 ○3
Regarding to t[……]阅读全文